OPSC ASO 2022 Question Paper with Answers

25 solved questions from the OPSC ASO 2022 paper (Advt. No. 26 of 2021-22), from every section: General Awareness, Reasoning, Mathematics, English, Odia. Each has the answer and an explanation of the options.

Answers are worked out by StudyTab, not taken from an answer key. Where a question is open to doubt, the explanation says why.

Practise all 400 OPSC ASO 2022 questions free on StudyTab →

General Awareness

Question 1

In the guidelines announced by Union Finance Minister in the 2022-2023 Budget, instead of using the term ‘Crypto Currency’, the term ________ is used.

  1. (a) Bitcoins Assets
  2. (b) Ethercoins Assets
  3. (c) Altcoins Assets
  4. (d) Virtual Digital Assets

Answer: (D) Virtual Digital Assets

  • (A), (B), (C) ✗ Bitcoin, Ether and altcoins are kinds of crypto. A tax law needs one term that covers them all.
  • (D) ✓ The 2022-23 Budget brought crypto and NFTs under the term virtual digital asset (VDA). The Finance Act, 2022 wrote it into the Income-tax Act, 1961.

The trap: three options name real crypto. The question asks for the legal term, and only one option is a category rather than a coin.

> Changed since: The Income-tax Act, 2025 replaced the 1961 Act from 1 April 2026. The term virtual digital asset and the 30% tax stay, but the sections are renumbered: the definition is now Section 2(111).


Question 2

Which State in India presented ‘Child Budget’ as part of the Annual State Budget ?

  1. (a) Andhra Pradesh
  2. (b) Gujarat
  3. (c) Sikkim
  4. (d) Madhya Pradesh

Answer: (D) Madhya Pradesh

  • (D) ✓ Madhya Pradesh presented a Child Budget for the first time with its 2022-23 budget in March 2022. It gathers the state's spending on children up to 18 years: nutrition, health, education and more.
  • (A) ✗, but defensible Andhra Pradesh had already started a Child Budget in 2021-22 (May 2021) and kept it in 2022-23. Read literally, the question has two true options. OPSC was most likely asking about the 2022 news, so we keep (D).
  • (B), (C) ✗ Gujarat and Sikkim were not part of this news.

The trap: the question says "presented", not "first presented". Read it as current affairs of early 2022, and (D) is the headline answer.


Question 3

The Government of India announced it's decision to convert 150 villages into ‘Villages of Excellence’ with technical assistance from ________.

  1. (a) Japan
  2. (b) Israel
  3. (c) USA
  4. (d) Netherlands

Answer: (B) Israel

  • (B) ✓ In January 2022 Agriculture Minister Narendra Singh Tomar announced that 150 villages around the Indo-Israel Centres of Excellence would become "Villages of Excellence", with Israeli technical help.
  • Half of them, 75 villages, were taken up in the first year, to mark 75 years of Independence.
  • (A), (C), (D) ✗ Japan, the USA and the Netherlands are not part of this plan. The villages are tied to centres India runs with Israel.

The trap: the Netherlands is also famous for farm technology. The clue is "Centres of Excellence": they come from the Indo-Israel Agricultural Project, and the villages plan grew out of them.


Question 4

Which one of the following is not the objective of ‘Operation Sajag’ launched by Delhi Police ?

  1. (a) To curb area domination exercise
  2. (b) Keeping tap on criminals
  3. (c) Intensive checking at pickets
  4. (d) Special rewards to traffic-friendly drivers

Answer: (D) Special rewards to traffic-friendly drivers

  • (D) ✓ Operation Sajag was an anti-street-crime drive of the North West district police, Delhi, launched on 4 October 2021. Rewarding good drivers is traffic work, not part of it.
  • (B), (C) ✗ The drive did keep tabs on criminals (printed "tap") and did intensive checking at pickets, with special combing operations.
  • (A) ✗ The police ran area domination exercises in this drive. "To curb" looks like a mix-up with its aim, to curb street crime. Read literally, (A) is also not an objective, but (D) is the one option plainly outside the drive.

The trap: three options describe patrolling and checking. The odd one out is the only option about traffic.


Question 5

The GSI has approved the setting up of country’s first Geological Park at ________.

  1. (a) Lamheta, Jabalpur
  2. (b) Kadagu, Karnataka
  3. (c) Idukki, Kerala
  4. (d) Talala Gir, Gujarat

Answer: (A) Lamheta, Jabalpur

  • (A) ✓ In January 2022 the Geological Survey of India (GSI) gave consent for the country's first geopark at Lamheta village, on the Narmada in Jabalpur district, Madhya Pradesh.
  • Lamheta Ghat gives its name to the Lameta Formation, rock beds famous for dinosaur fossils and eggs.
  • (B), (C), (D) ✗ Kodagu (printed "Kadagu"), Idukki and Talala Gir were not chosen. The first two are Western Ghats hill districts; Talala lies by the Gir forest.

The trap: all four are well-known scenic places. A geological park is about rocks and fossils, and Lamheta's are the most famous of the four.

Reasoning

Question 1

Select the correct option that indicates the arrangement of the given words in the order in which they appear in a telephone directory :
(I) Krishanmurty
(II) Krishnamurthy
(III) Krishnmurthi
(IV) Krishanmurthy
(V) Krishnamurti

  1. (a) (IV), (I), (II), (V), (III)
  2. (b) (IV), (I), (II), (III), (V)
  3. (c) (IV), (V), (II), (III), (I)
  4. (d) (IV), (III), (V), (III), (II)

Answer: (A) (IV), (I), (II), (V), (III)

All five begin "Krish"; the sixth letter splits them into two groups.

  • "a" group: (I) and (IV) both run "Krishanmurt". Then (IV) has h and (I) has y, so (IV), (I).
  • "n" group: after "Krishn", (II) and (V) have a but (III) has m, so (III) is last.
  • Between (II) and (V), after "Krishnamurt" comes h in (II) and i in (V): (II), (V).
  • (B) ✗ puts (III) before (V), though "Krishnm" comes after "Krishna".
  • (C) ✗ puts (I) last, though it starts "Krisha".
  • (D) ✗ repeats (III) and drops (I): a misprinted option.

The trap: the names differ by one letter deep inside. Compare column by column from the left; don't judge by length or by the "-thy / -ti" endings.


Question 2

In a certain code language, ‘VIRTUE’ is coded as ‘201’ and ‘TRAGEDY’ is coded as ‘218’. How will ‘PROFANE’ be coded in that language ?

  1. (a) 570
  2. (b) 342
  3. (c) 432
  4. (d) 456

Answer: (B) 342

Rule: give each letter its reverse value (Z = 1, Y = 2 … A = 26), add them, and multiply by the number of vowels.

WordReverse totalVowelsCode
VIRTUE5+18+9+7+6+22 = 67I, U, E = 367 × 3 = 201 ✓
TRAGEDY7+9+26+20+22+23+2 = 109A, E = 2109 × 2 = 218 ✓
PROFANE11+9+12+21+26+13+22 = 114O, A, E = 3114 × 3 = 342
  • (A) ✗ 570 = 114 × 5; no feature of the examples gives 5.
  • (C) ✗ 432 is not a multiple of 114.
  • (D) ✗ 456 = 114 × 4, the consonant count. That works for VIRTUE (3 consonants) but gives 545 for TRAGEDY, not 218.

The trap: VIRTUE has 3 vowels and 3 consonants, so it cannot tell the two rules apart. Only TRAGEDY settles it.


Question 3

Directions (Q. Nos. 3 to 5) : One hundred and twenty five cubes of the same size are arranged in the form of a cube on a table. Then a column of five cubes is removed from each of the four corners. All the exposed faces of the rest of the solid (except the face touching the table) are coloured red. Now, answer these questions based on the above statement :

How many small cubes are there in the solid after the removal of the columns ?

  1. (a) 120
  2. (b) 110
  3. (c) 105
  4. (d) 100

Answer: (C) 105

  • 125 cubes make a 5 × 5 × 5 cube: 5 layers of 25.
  • A corner column runs from the table to the top, so it holds 5 cubes.
  • Four corners: 4 × 5 = 20 cubes removed.
  • Left: 125 − 20 = 105.
  • (A) ✗ 120 removes only one column.
  • (B) ✗ 110 removes three columns.
  • (D) ✗ 100 removes five columns' worth.

The trap: a "column" is a vertical stack through all 5 layers, not a single corner cube. Taking away only the 8 corner cubes would leave 117, which is not offered.


Question 4

Directions (Q. Nos. 3 to 5) : One hundred and twenty five cubes of the same size are arranged in the form of a cube on a table. Then a column of five cubes is removed from each of the four corners. All the exposed faces of the rest of the solid (except the face touching the table) are coloured red. Now, answer these questions based on the above statement :

How many cubes do not have any coloured face ?

  1. (a) 12
  2. (b) 24
  3. (c) 36
  4. (d) 48

Answer: (C) 36

Look at one layer: 25 − 4 = 21 cubes.

  • The 12 outer cubes each show a side to the outside, either the old wall or the gap left by a removed column. All are red.
  • The centre 3 × 3 = 9 cubes are boxed in on all four sides.
  • In the top layer these 9 have their top face red.
  • In the lower 4 layers their top is covered by the layer above and their bottom rests on cubes or on the table, which is not coloured. So they stay plain: 9 × 4 = 36.
  • (A) ✗ 12 = the outer ring of one layer, all red.
  • (B) ✗ 24 fits no group of plain cubes.
  • (D) ✗ 48 = outer rings of 4 layers, all red.

The trap: the usual "inner cube" formula, (5 − 2)³ = 27, assumes the bottom is coloured too. Here the table face stays plain, so the bottom layer's centre counts.


Question 5

Directions (Q. Nos. 3 to 5) : One hundred and twenty five cubes of the same size are arranged in the form of a cube on a table. Then a column of five cubes is removed from each of the four corners. All the exposed faces of the rest of the solid (except the face touching the table) are coloured red. Now, answer these questions based on the above statement :

How many cubes have only one red face ?

  1. (a) 40
  2. (b) 25
  3. (c) 20
  4. (d) 15

Answer: (B) 25

  • Top layer: the centre 3 × 3 = 9 cubes show only their top face. That is 9.
  • Each side has 3 cubes between the two removed corners. The two beside a gap show the outer wall and the gap: 2 red faces. Only the middle one shows a single face.
  • 4 sides give 4 such middle cubes per layer, in the lower 4 layers (in the top layer they also show the top): 4 × 4 = 16.
  • Total: 9 + 16 = 25.
  • (A) ✗ 40 counts cubes that really show two faces.
  • (C) ✗ 20 and (D) ✗ 15 miss some one-face cubes.

The trap: removing a corner column opens a new face on the cubes beside it. Those cubes now have 2 red faces, not 1.

Mathematics

Question 51

1/1.3+1/3.5+1/5.7+1/7.9 = ?

  1. (a) 5/11
  2. (b) 6/11
  3. (c) 9/4
  4. (d) 4/9

Answer: (D) 4/9

The dot in "1.3" looks like a decimal point but means multiplication: 1/(1×3)+1/(3×5)+1/(5×7)+1/(7×9). Read as decimals, the sum is about 1.36, which is no option.

  • Split each term: the two factors differ by 2, so 1/n(n+2)=1/2(1/n-1/(n+2)).
  • Add: 1/2(1-1/3+1/3-1/5+1/5-1/7+1/7-1/9). All the middle terms cancel.
  • Result: 1/2(1-1/9)=1/2×8/9= 4/9.
  • Check: 1/3+1/15+1/35+1/63=(105+21+9+5)/315=140/315=4/9.
  • (A) 5/11 ✗ is the sum with one extra term, 1/(9×11): half of (1-1/11). (B) ✗ does not come from this sum. (C) ✗ is 4/9 turned upside down.

The trap: the printed dot. Read "1.3" as one-point-three and the sum comes to about 1.36, so no option fits and time is lost.

Fastest: (1/first − 1/last) ÷ gap = (1 − 1/9) ÷ 2 = 4/9.


Question 52

Determine the smallest 3-digit number which is exactly divisible by 6 and 12 ?

  1. (a) 96
  2. (b) 84
  3. (c) 108
  4. (d) 120

Answer: (C) 108

  • LCM first: the LCM of 6 and 12 is 12, because 12 is already a multiple of 6. So we need the smallest 3-digit multiple of 12.
  • Start at 100: 100 ÷ 12 = 8, remainder 4.
  • Go up to the next multiple: 100 + (12 - 4) = 108. Check: 108 = 12 × 9 = 6 × 18.
  • (A) 96, (B) 84 ✗ are multiples of 12 but have only two digits.
  • (D) 120 ✗ is a multiple of 12, but it is larger than 108.

The trap: 96 and 84 pass the divisibility test, so a student who only checks "divisible by 6 and 12" can tick them. Read "3-digit" first, then test.


Question 53

What is the HCF of 1/5, 2/7 and 3/11 ?

  1. (a) 1/385
  2. (b) 6
  3. (c) 1/35
  4. (d) 5/77

Answer: (A) 1/385

  • Rule: HCF of fractions = HCF of numerators ÷ LCM of denominators.
  • Numerators 1, 2, 3: HCF = 1.
  • Denominators 5, 7, 11 are all prime, so LCM = 5 × 7 × 11 = 385.
  • So the HCF is 1/385. Check: dividing each fraction by 1/385 gives whole numbers, 77, 110 and 105.
  • (B) 6 ✗ is the LCM of the fractions. An HCF can't be larger than the smallest fraction, 1/5.
  • (C) 1/35, (D) 5/77 ✗ don't divide all three: 3/11 ÷ 1/35 = 105/11 and 1/5 ÷ 5/77 = 77/25, not whole.

The trap: swapping the two rules. The LCM of fractions is the reverse, LCM of numerators ÷ HCF of denominators = 6/1 = 6, and OPSC put exactly that in option (B).


Question 54

0.03 × 0.0165 is equal to :

  1. (a) 4.95 × 10⁻³
  2. (b) 4.95 × 10⁻⁴
  3. (c) 4.95 × 10⁻⁵
  4. (d) 4.95 × 10⁻⁶

Answer: (B) 4.95 × 10⁻⁴

  • Multiply as whole numbers: 3 × 165 = 495.
  • Count decimal places: 0.03 has 2 and 0.0165 has 4, a total of 6. So the product is 0.000495.
  • Scientific form: moving the point 4 places to the right gives 4.95, so 0.000495 = 4.95 × 10⁻⁴.
  • (A) ✗ 4.95 × 10⁻³ = 0.00495, ten times too big.
  • (C), (D) ✗ are ten and a hundred times too small.

The trap: a slip of one decimal place. All four options share 4.95, so the question tests only the count of places.

Fastest: write both in powers of ten: (3 × 10⁻²) × (1.65 × 10⁻²) = 4.95 × 10⁻⁴.


Question 55

((799+267)²-(799-267)²)/(799 × 267) = ?

  1. (a) 532
  2. (b) 1066
  3. (c) 2
  4. (d) 4

Answer: (D) 4

  • Identity: (a+b)²-(a-b)² = (a²+2ab+b²)-(a²-2ab+b²) = 4ab.
  • Here a = 799 and b = 267, so the top is 4 × 799 × 267.
  • Divide: (4 × 799 × 267)/(799 × 267) = 4. No big multiplication is needed.
  • (A) 532 ✗ is 799 - 267, and (B) 1066 ✗ is 799 + 267: numbers from inside the brackets.
  • (C) 2 ✗ forgets that the cross terms add up: +2ab minus -2ab gives 4ab, not 2ab.

The trap: the big numbers tempt you to square 1066 and 532. Spot the pattern first: the answer is 4 whatever a and b are.

Check with small numbers: a = 2, b = 1 gives (3² - 1²)/(2 × 1) = 8/2 = 4.

English

Question 1

Change the active voice into passive voice : I will clean the house every Saturday. The house ________ by me every Saturday.

  1. (a) cleaned
  2. (b) will cleaned
  3. (c) will be cleaned
  4. (d) None of these

Answer: (C) will be cleaned

  • (C) ✓ The passive of the simple future is will be + past participle. "I will clean the house" becomes "The house will be cleaned by me."
  • (A) ✗ "The house cleaned by me" has no be and no future, so it is not a passive verb at all.
  • (B) ✗ After a modal like will comes the base form. "Will cleaned" skips the be that every passive needs.
  • (D) ✗ (C) is correct, so "None of these" fails.

The trap: students change clean to cleaned and stop there. Keep the tense of the active (will), add be, then the past participle. The object, the house, becomes the subject.


Question 2

People ________ walk on grass.

  1. (a) couldn't
  2. (b) needn't
  3. (c) mustn't
  4. (d) may not

Answer: (C) mustn't

  • (C) ✓ Mustn't (must not) says something is not allowed: the familiar "Keep off the grass" rule.
  • (B) ✗ Needn't means not necessary. "People needn't walk on grass" makes walking there optional, which is not a ban.
  • (A) ✗ Couldn't is past ability or past permission. It does not state a rule that holds now.
  • (D) ✗ May not can refuse permission in formal notices ("Visitors may not take photos"). But on its own it most often reads as possibility: "perhaps people don't walk on grass". For a plain rule, mustn't is the exact modal.

The trap: mustn't and needn't look alike but are opposites in force. Mustn't = don't do it; needn't = you don't have to.


Question 3

Choose the correct word order :

  1. (a) Why she did leave so early ?
  2. (b) Why did she leave so early ?
  3. (c) Why did so early she leave ?
  4. (d) Why so early did she leave ?

Answer: (B) Why did she leave so early ?

  • (B) ✓ A wh-question follows wh-word + auxiliary + subject + main verb: Why + did + she + leave + so early.
  • (A) ✗ "Why she did leave" keeps statement order, with the subject before did. That order belongs in a reported question: "I asked why she left so early."
  • (C), (D) ✗ The adverb phrase "so early" goes after the verb. It cannot come between did and the subject, or before did.

The trap: in a question the auxiliary did jumps in front of the subject, and the main verb goes back to its base form (leave, not left).


Question 4

Select same meaning of the underlined word : Take care not to get hurt with the steam from the Kettle.

  1. (a) Burnt
  2. (b) Bruised
  3. (c) Scalded
  4. (d) Cut

Answer: (C) Scalded

  • (C) ✓ To scald is to burn the skin with hot liquid or steam. Steam from a kettle is the textbook case.
  • (A) ✗ Burnt is close, since a scald is a kind of burn. But burn is the general word, usually for fire or a hot surface. For steam, English has the exact word.
  • (B) ✗ A bruise comes from a blow: the skin turns dark but is not broken.
  • (D) ✗ A cut needs a sharp edge.

The trap: burnt looks safe because it is related. The question rewards the most exact word for an injury by steam: "Take care not to get scalded."


Question 5

________ his principles, he has to be very careful.

  1. (a) With regard of
  2. (b) With regard on
  3. (c) With regard to
  4. (d) None of these

Answer: (C) With regard to

  • (C) ✓ The fixed phrase is with regard to, meaning "about" or "concerning": "With regard to his principles, he has to be very careful."
  • (A), (B) ✗ "With regard of" and "with regard on" are not English. In this phrase regard always takes to.
  • (D) ✗ (C) is correct, so "None of these" fails.

The trap: the phrase has several correct relatives: in regard to, as regards and regarding. "With regards to", with an s, is common in speech but best avoided in formal writing. Of and on never fit.

Odia

Question 101

ନିର୍ଦ୍ଦେଶ (ପ୍ରଶ୍ନସଂଖ୍ୟା 101-110) : ଠିକ୍ ଶବ୍ଦ (ଉତ୍ତର) ଚିହ୍ନଟ କର :

  1. (a) ଅନିର୍ବାର୍ଯ୍ୟ
  2. (b) ଅନୀବାର୍ଯ୍ୟ
  3. (c) ଅନିବାର୍ଯ୍ୟ
  4. (d) ଅନିର୍ବାଯ୍ୟ

ଉତ୍ତର: (C) ଅନିବାର୍ଯ୍ୟ

  • (C) ✓ 'ନି' ଉପସର୍ଗ + √ବୃ ଧାତୁରୁ ନିବାରଣ (ରୋକିବା)। ଯାହାକୁ ରୋକିହୁଏ ତାହା 'ନିବାର୍ଯ୍ୟ'; ଆଗରେ 'ଅ' ଲାଗି ଅନିବାର୍ଯ୍ୟ = ଯାହାକୁ ରୋକି ହୁଏ ନାହିଁ, ଅବଶ୍ୟମ୍ଭାବୀ।
  • (A) ✗ 'ବା' ଉପରେ ଅଦରକାରୀ ରେଫ ଲାଗିଛି।
  • (B) ✗ 'ନି' ସ୍ଥାନରେ ଦୀର୍ଘ ନୀ ଭୁଲ୍।
  • (D) ✗ ରେଫ 'ବା' ଉପରକୁ ଚାଲିଯାଇଛି ଓ ଶେଷର 'ର୍ଯ୍ୟ' ରେଫ ହରାଇଛି।

ଫାନ୍ଦ: 'ନିର୍ବାଣ', 'ନିର୍ବାହ' ପରି ଶବ୍ଦ ମନେ ପଡ଼ି 'ବ' ଉପରେ ରେଫ ଦେବାକୁ ଇଚ୍ଛା ହୁଏ। ମୂଳ ଶବ୍ଦ 'ନିବାରଣ'ରେ ଉପସର୍ଗ 'ନି', 'ନିର୍' ନୁହେଁ।


Question 102

ନିର୍ଦ୍ଦେଶ (ପ୍ରଶ୍ନସଂଖ୍ୟା 101-110) : ଠିକ୍ ଶବ୍ଦ (ଉତ୍ତର) ଚିହ୍ନଟ କର :

  1. (a) ନିଷ୍ଫଳ
  2. (b) ନିଷ୍ପଳ
  3. (c) ନିଃଷ୍ଫଳ
  4. (d) ନୀଷ୍ପଳ

ଉତ୍ତର: (A) ନିଷ୍ଫଳ

  • (A) ✓ ନିଃ + ଫଳ: 'ଇ' ପରେ ଥିବା ବିସର୍ଗ, ପରେ 'ଫ' ଆସିଲେ, 'ଷ୍' ହୁଏ। ତେଣୁ ନିଷ୍ଫଳ = ଫଳହୀନ, ବିଫଳ।
  • (B) ✗ ଯୁକ୍ତାକ୍ଷରର ତଳ ଅକ୍ଷର ଫ ନୁହେଁ; ମୂଳ ଶବ୍ଦ 'ଫଳ' ହିଁ ବଦଳିଗଲା।
  • (C) ✗ ବିସର୍ଗ ଯେତେବେଳେ 'ଷ୍' ହୋଇସାରିଛି, ପୁଣି ବିସର୍ଗ ଲେଖିବା ଭୁଲ୍।
  • (D) ✗ ଦୀର୍ଘ ନୀ ଓ ଭୁଲ୍ ଯୁକ୍ତାକ୍ଷର: ଦୁଇଟି ଭୁଲ୍।

ଫାନ୍ଦ: ସନ୍ଧି ଭାଙ୍ଗି ଦେଖିଲେ 'ନିଃ' ଓ 'ଫଳ' ଦୁହେଁ ଦିଶନ୍ତି, ତେଣୁ (C) ଠିକ୍ ମନେହୁଏ। ସନ୍ଧି ହେବା ପରେ ବିସର୍ଗ ନିଜେ ବଦଳିଯାଏ; ଦୁଇଟି ରୂପ ଏକାଠି ରହେ ନାହିଁ।


Question 103

ନିର୍ଦ୍ଦେଶ (ପ୍ରଶ୍ନସଂଖ୍ୟା 101-110) : ଠିକ୍ ଶବ୍ଦ (ଉତ୍ତର) ଚିହ୍ନଟ କର :

  1. (a) ଆର୍ଶିବାଦ
  2. (b) ଆଶ୍ରିବାଦ
  3. (c) ଆଶ୍ରୀବାଦ
  4. (d) ଆଶୀର୍ବାଦ

ଉତ୍ତର: (D) ଆଶୀର୍ବାଦ

  • (D) ✓ ଆଶୀଃ (ଶୁଭ କାମନା) + ବାଦ: ବିସର୍ଗ ପରେ 'ବ' ଆସିଲେ ବିସର୍ଗ 'ର୍' ହୁଏ, ଯାହା 'ବା' ଉପରେ ରେଫ ଭାବେ ବସେ।
  • (A) ✗ ରେଫ 'ଶି' ଉପରେ, ଓ 'ଶି' ହ୍ରସ୍ୱ।
  • (B), (C) ✗ 'ଶ' ତଳେ ର-ଫଳା; କିନ୍ତୁ 'ର୍' ଉଚ୍ଚାରଣ 'ଶୀ' ପରେ ଆସେ, ଆଗରେ ନୁହେଁ।

ଫାନ୍ଦ: କଥିତ ଭାଷାରେ 'ଆଶିର୍ବାଦ' ବା 'ଆଶ୍ରୀବାଦ' ପରି ଶୁଭେ। ମନେରଖନ୍ତୁ: 'ଶୀ' ଦୀର୍ଘ, ଓ ରେଫ ସବୁବେଳେ ସେହି ଅକ୍ଷର ଉପରେ ବସେ ଯାହା 'ର୍' ଉଚ୍ଚାରଣର ପରେ ଆସେ।


Question 104

ନିର୍ଦ୍ଦେଶ (ପ୍ରଶ୍ନସଂଖ୍ୟା 101-110) : ଠିକ୍ ଶବ୍ଦ (ଉତ୍ତର) ଚିହ୍ନଟ କର :

  1. (a) ଓତଃପୋତ
  2. (b) ଓତଃପ୍ରୋତ
  3. (c) ଓତଂର୍ପୋତ
  4. (d) ଓତପ୍ରୋତ

ଉତ୍ତର: (D) ଓତପ୍ରୋତ

  • (D) ✓ ଓତ (ଲମ୍ବ ଦିଗରେ ବୁଣା) + ପ୍ରୋତ (ଓସାର ଦିଗରେ ବୁଣା): ଲୁଗାର ଲମ୍ବ ଓ ଓସାର ସୂତା ପରି ସବୁଆଡ଼େ ବ୍ୟାପିଥିବା, ଗଭୀର ଭାବେ ଜଡ଼ିତ।
  • (A) ✗ ଅଦରକାରୀ ବିସର୍ଗ, ଆଉ 'ପ୍ରୋ'ର ର-ଫଳା ନାହିଁ।
  • (B) ✗ 'ଓତ' ଶବ୍ଦରେ ବିସର୍ଗ ନାହିଁ; 'ମନଃ', 'ଶିରଃ' ପରି ଶବ୍ଦ ମନେ ପଡ଼ି ଏହା ଆସେ।
  • (C) ✗ 'ତ' ଉପରେ ଏକ ଚିହ୍ନ ଓ 'ପୋ' ଉପରେ ରେଫ; ଏଠାରେ 'ର' 'ପ' ତଳେ ର-ଫଳା ହେବା କଥା।

ଫାନ୍ଦ: ଏହା ଦ୍ୱନ୍ଦ୍ୱ ସମାସ, ବିସର୍ଗ ସନ୍ଧି ନୁହେଁ: ଦୁଇଟି ଶବ୍ଦ ସିଧାସଳଖ ଯୋଡ଼ି ହୁଏ, ମଝିରେ କୌଣସି ଚିହ୍ନ ଯୋଗ ହୁଏ ନାହିଁ।


Question 105

ନିର୍ଦ୍ଦେଶ (ପ୍ରଶ୍ନସଂଖ୍ୟା 101-110) : ଠିକ୍ ଶବ୍ଦ (ଉତ୍ତର) ଚିହ୍ନଟ କର :

  1. (a) ପିୟୂଷ
  2. (b) ପୀୟୁଷ
  3. (c) ପିୟୁଷ
  4. (d) ପୀୟୂଷ

ଉତ୍ତର: (D) ପୀୟୂଷ

  • (D) ✓ ପୀୟୂଷ = ଅମୃତ (ଦୁଧ, ମଧୁର ରସ ଅର୍ଥରେ ମଧ୍ୟ)। ଏଥିରେ 'ପୀ' ଓ 'ୟୂ' ଦୁହେଁ ଦୀର୍ଘ।
  • (A) ✗ 'ପି' ହ୍ରସ୍ୱ।
  • (B) ✗ 'ୟୁ' ହ୍ରସ୍ୱ।
  • (C) ✗ ଦୁଇଟି ସ୍ୱର ଯାକ ହ୍ରସ୍ୱ।

ଫାନ୍ଦ: ଚାରିଟି ବିକଳ୍ପ ଦୁଇ ସ୍ୱରର ଚାରି ମିଶ୍ରଣ। ଗୋଟିଏ ସ୍ୱର ଠିକ୍ ଜାଣିଲେ ଦୁଇଟି ବିକଳ୍ପ ବାଦ୍ ପଡ଼େ; ଦୁହେଁ ଦୀର୍ଘ ବୋଲି ମନେରଖନ୍ତୁ।


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